If the diagonal of a quadrilateral is doubled and the offsets remain the same, the area becomes:

If the diagonal of a quadrilateral is doubled and the offsets remain the same, the area becomes:
  1. Same
  2. Twice
  3. Half
  4. Four times

Solution

Area $= \dfrac{1}{2} d (h_{1}+h_{2})$ is directly proportional to $d$, so doubling $d$ doubles the area.

Asked in: IMO

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