If the de Broglie wavelength of electron is $728.14 \mathrm{~nm}$, its kinetic energy in $\mathrm{J}$ is:…

If the de Broglie wavelength of electron is $728.14 \mathrm{~nm}$, its kinetic energy in $\mathrm{J}$ is: (mass of electron $=9.1 \times 10^{-31} \mathrm{~kg} ; \mathrm{h}=6.626 \times 10^{-34} \mathrm{~J} \mathrm{~s}$)
  1. $4.55 \times 10^{-25}$
  2. $9.1 \times 10^{-25}$
  3. $4.55 \times 10^{-23}$
  4. $9.1 \times 10^{-23}$

Solution

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Asked in: AP EAMCET 2017 (25 Apr Shift 2)

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