If $n=6$, the correct sequence for filling of electrons will be
- $n s \longrightarrow(n-1) d \longrightarrow(n-2) f \longrightarrow n p$
- $n s \longrightarrow(n-2) f \longrightarrow n p \longrightarrow(n-1) d$
- $n s \longrightarrow n p \longrightarrow(n-1) d \longrightarrow(n-2) f$
- $n s \longrightarrow(n-2) f \longrightarrow(n-1) d \longrightarrow n p$
Solution
Asked in: NEET 2011 (Screening)
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