If the constant term in the binomial expansion of x - k x 2 10 is 405 , then k equals :

If the constant term in the binomial expansion of x-kx210 is 405, then k equals :
  1. 9
  2. 1
  3. 3
  4. 2

Solution

Tr+1=Cr10-kx2rx10-r

=Cr·10-kr·x5-5r2

for constant term

5-5r2=0  r=2

T3=C210·k2=405

10(9)2k2=405

k2=9

k=3

Asked in: JEE Main 2020 (06 Sep Shift 2)

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