If the conductivity of a $0.5 \mathrm{M} \mathrm{KCl}$ solution at $298 \mathrm{~K}$ is $0.024 \mathrm{~S} \mathrm{~cm}^{-1}$, then the molar conductivity of the solution would be $\mathrm{Scm}^2 \mathrm{~mol}^{-1}$.

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Aicharya · Accepted Answer

Electrolytic conductivity, $\kappa=0.024 \mathrm{~S} \mathrm{~cm}^{-1}$ Molar concentration $=0.5 \mathrm{M}$ $ \begin{aligned} \Lambda_{\mathrm{m}}^0(	ext { Molar conductivity }) & =\frac{\kappa 	imes 1000}{M} \ =\frac{0.024 	imes 1000}{0.5} & =48 \mathrm{~S} \mathrm{~cm}^2 \mathrm{~mol}^{-1} . \end{aligned} $

If the conductivity of a $0.5 \mathrm{M} \mathrm{KCl}$ solution at $298 \mathrm{~K}$ is $0.024 \mathrm{~S}…

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