If the concentration of $\mathrm{OH}^{-}$ions in the reaction $\mathrm{Fe}(\mathrm{OH})_3(\mathrm{~s})…
If the concentration of $\mathrm{OH}^{-}$ions in the reaction $\mathrm{Fe}(\mathrm{OH})_3(\mathrm{~s}) \rightleftharpoons \mathrm{Fe}^{3+}(\mathrm{aq})+3 \mathrm{OH}^{-}(\mathrm{aq})$ is decreased by $\frac{1}{4}$ times, then equilibrium concentration of $\mathrm{Fe}^{3+}$ will increase by
4 times
8 times
16 times
64 times
Solution
To maintain the constant value of $\mathrm{K}_c$, the concentration of $\mathrm{Fe}^{3+}$ ion will increase by 64 times.