If the coefficients of the equation whose roots are $k$ times the roots of the equation, $x^3+\frac{1}{4}…
- $3$
- $12$
- $9$
- $4$
Solution

The equation whose roots are $\mathrm{k}$ times the roots of the eq. (i), is $\begin{aligned} & \left(\frac{x}{k}\right)^3+\frac{1}{4}\left(\frac{x}{k}\right)^3-\frac{1}{16}\left(\frac{x}{k}\right)+\frac{1}{144}=0 \\ & \Rightarrow x^3+\frac{k}{4} x^2-\frac{k^2}{16} x+\frac{k^3}{144}=0 \end{aligned}$ Also given that, coefficients of the above equation are integer. $k=12$
Asked in: AP EAMCET 2016