If the charge to mass ratio of an electron is ' $\mathrm{A}$ ' $\mathrm{C} / \mathrm{kg}$, then the…
If the charge to mass ratio of an electron is ' $\mathrm{A}$ ' $\mathrm{C} / \mathrm{kg}$, then the gyromagnetic ratio of an orbital electron in $\mathrm{C} / \mathrm{kg}$ is
$\frac{\mathrm{A}}{4}$
$\mathrm{A}$
$2 \mathrm{~A}$
$\frac{\mathrm{A}}{2}$
Solution
$\text { Gyromagnetic ratio }=\frac{\text { Magnetic Moment }}{\text { Angular Momentum }}=\frac{\mathrm{e}}{2 \mathrm{~m}}=\frac{\mathrm{A}}{2}$
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