If the bond length and dipole moment of a diatomic molecule are $1.25 \mathrm{~A}$ and $1.0 \mathrm{D}$ respectively, what is the per cent ionic character of the bond?

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Aicharya · Accepted Answer

$\mu$ experimental $=$ Dipole moment $	imes 10^{-18}$ $\mu$ theoretical $=$ Bond length $	imes 4.8 	imes 10^{-10} 	imes 10^{-8} \mathrm{esu} 	imes \mathrm{cm}$ Per cent ionic character $=\frac{\mu_{	ext {experimental }}}{\mu_{	ext {theoretical }}} 	imes 100$ $=\frac{1.0 	imes 10^{-18} 	imes 100}{1.25 	imes 4.8 	imes 10^{-10} 	imes 10^{-8}}=16.66 \%$ ~

If the bond length and dipole moment of a diatomic molecule are $1.25 \mathrm{~A}$ and $1.0 \mathrm{D}$…

Solution