If the binding energy of N 14 is 7 . 5   MeV per nucleon and that of N 15 is 7 . 7   MeV per…

If the binding energy of N14 is 7.5 MeV per nucleon and that of N15 is7.7 MeV per nucleon. then the energy required to remove a neutron from N15 is
  1. 5.25 MeV
  2. 0.2 MeV
  3. 10.5 MeV
  4. 0.4 MeV

Solution

The total binding energy,

N14=7.5×14 MeV

N15=7.7×15 MeV

The energy required to remove a neutron from N15,

E=BE N15-BE N14

E=7.7×15-7.5×14 MeV

⇒  E=10.5 MeV

Asked in: AP EAMCET 2019 (21 Apr Shift 2)

Practice more Nuclear Physics questions on Aicharya