If the binding energy of ground state electron in a hydrogen atom is 13 . 6   eV , then, the energy…

If the binding energy of ground state electron in a hydrogen atom is 13.6 eV, then, the energy required to remove the electron from the second excited state of Li 2+ will be: x×10-1 eV. The value of x is _____.

Solution

Given:

Binding energy, EH=E0=13.6 eV.

Now for hydrogen like atom, we can write

ELi2+=E0Z2n2=13.6×99=13.6 eV

=136×10-1 eV

Therefore, x=136.

Asked in: JEE Main 2023 (31 Jan Shift 2)

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