If the angular velocity of earth's spin is increased such that the bodies at the equator start floating, the duration of the day would be approximately :
(Take : $g = 10 {ms}^{- 2}$ , the radius of earth, $R = 6400 \times 10^{3} m$ , Take $π = 3.14$ )

Question

If the angular velocity of earth's spin is increased such that the bodies at the equator start floating, the duration of the day would be approximately :
(Take :

g = 10 {ms}^{- 2}

, the radius of earth,

R = 6400 \times 10^{3} m

, Take

π = 3.14

)

Aicharya · Accepted Answer

For objects to float, m g = m &#969; 2 R &#969; = angular velocity of the earth. R = Radius of earth &#969; = g R &#160; &#160; &#160; . . . 1 Duration of day = T T = 2 &#960; &#969; &#160; &#160; &#160; . . . 2 &#8658; T = 2 &#960; R g = 2 &#960; 6400 &#215; 10 3 10 &#8658; T 60 = 83 . 775 minutes &#8771; 84 minutes

If the angular velocity of earth's spin is increased such that the bodies at the equator start floating,…

Solution

If the angular velocity of earth&#39;s spin is increased such that the bodies at the equator start floating,…

Solution

If the angular velocity of earth's spin is increased such that the bodies at the equator start floating,…