If the angles of a triangle are in the ratio $4: 1: 1$, then the ratio of the longest side to its perimeter is

If the angles of a triangle are in the ratio $4: 1: 1$, then the ratio of the longest side to its perimeter is
  1. $\sqrt{3}:(2+\sqrt{3})$
  2. $2:(1+\sqrt{3})$
  3. $1:(2+\sqrt{3})$
  4. $2: 3$

Solution

Let the angles of the triangle be $4 x, x$ and $x$. $\begin{aligned} \therefore \quad & 4 x+x+x=180^{\circ} \Rightarrow 6 x=180^{\circ} \Rightarrow x=30^{\circ} \\ & \frac{\sin 120^{\circ}}{\mathrm{a}}=\frac{\sin 30^{\circ}}{\mathrm{b}}=\frac{\sin 30^{\circ}}{\mathrm{c}} \\ \therefore \quad & \mathrm{a}:(\mathrm{a}+\mathrm{b}+\mathrm{c}) \\ & =\left(\sin 120^{\circ}\right):\left(\sin 120^{\circ}+\sin 30^{\circ}+\sin 30^{\circ}\right) \\ & =\frac{\sqrt{3}}{2}: \frac{\sqrt{3}+2}{2}=\sqrt{3}:(\sqrt{3}+2) \end{aligned}$

Asked in: MHT CET 2023 (11 May Shift 2)

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