If the absolute maximum value of the function f x = x 2 - 2 x + 7 e 4 x 3 - 12 x 2 - 180 x + 31 in the…

If the absolute maximum value of the function fx=x2-2x+7e4x3-12x2-180x+31in the interval -3,0 is fα, then
  1. α=0
  2. α=-3
  3. α-1,0
  4. α-3,-1

Solution

Given,

fx=x2-2x+7e4x3-12x2-180x+31

Now differentiating the function to find function is increasing or decreasing,

f'x=e4x3-12x2-180x+3112x2-2x-15+2x-1

f'x=e4x3-12x2-180x+3112x+3x-5+2x-1

f'x<0 for x-3,0

So, fxis decreasing function on -3,0

The absolute maximum value of the function fx is at x=-3

α=-3

Asked in: JEE Main 2022 (25 Jul Shift 1)

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