If ∫ tan x 1 + tan x + tan 2 x d x = x - K A tan - 1 K tan x + 1 A + C , ( C is a constant of…

If tanx1+tanx+tan2xdx=x-KAtan-1Ktanx+1A+C, (C is a constant of integration), then the ordered pair K,A is equal to
  1. 2,1
  2. 2,3
  3. -2,1
  4. -2,3

Solution

Let I=tanx1+tanx+tan2xdx

I=1-sec2x1+tanx+tan2xdx

I=x-dt1+t+t2

Where, tanx=tsec2xdx=dt

 I=x-132tan-1t+1232+C, where C is the constant of integration.

=x-23tan-12tanx+13+C

 K=2 & A=3.

Asked in: JEE Main 2018 (16 Apr Online)

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