If sum of the slopes of lines represented by $x^2-2 x y an heta-y^2=0$ is 4 , then $ heta=$

Question

If sum of the slopes of lines represented by $x^2-2 x y 	an 	heta-y^2=0$ is 4 , then $	heta=$

Aicharya · Accepted Answer

$\begin{aligned} & m_1+m_2=\frac{-2 h}{b} \ & \Rightarrow 4=\frac{2 	an 	heta}{-1} \ & \Rightarrow 	an 	heta=-2 \ & \Rightarrow 	heta=	an ^{-1}(-2)\end{aligned}$

If sum of the slopes of lines represented by $x^2-2 x y \tan \theta-y^2=0$ is 4 , then $\theta=$

Solution