If speed $V$, area $A$ and force $F$ are chosen as fundamental units, then the dimension of Young's modulus will be:

Question

Aicharya · Accepted Answer

Y &#8733; F a V b A c &#160;&#160; Y = F A M L T - 2 L 2 &#8733; M 1 L 1 T - 2 a L 1 T - 1 b L 2 c M 1 L - 1 T - 2 &#8733; M a La + b + 2 cT - 2 a - b a &#160; + &#160; b &#160; + &#160; 2 c &#160; = &#160; &#8211; 1 &#8211; 2 a &#160; + &#160; b &#160; = &#160; &#8211; 2 a &#160; = &#160; 1 , &#160; b &#160; = &#160; 0 , &#160; c &#160; = &#160; &#8211; 1 Y = F 1 V 0 A - 1

If speed $V$, area $A$ and force $F$ are chosen as fundamental units, then the dimension of Young's modulus…

Solution