If seven women and seven men are to be seated around a circular table such that there is a man on either…
If seven women and seven men are to be seated around a circular table such that there is a man on either side of every woman, then the number of seating arrangements is
$6 ! 7 !$
$(6 !)^2$
$(7 !)^2$
7 !
Solution
7 women can be arranged around a circular table in 6 ! ways.
Among these 7 men can sit in 7 ! ways. Hence, number of seating arrangement $=7 ! \times 6 !$