If roots of the equation $x^2-b x+c=0$ be two consectutive integers, then $b^2-4 c$ equals

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Aicharya · Accepted Answer

Let $\alpha, \alpha+1$ be roots $ \begin{aligned} & \alpha+\alpha+1=b \ & \alpha(\alpha+1)=c \ & 	herefore b^2-4 c=(2 \alpha+1)^2-4 \alpha(\alpha+1)=1 . \end{aligned} $

If roots of the equation $x^2-b x+c=0$ be two consectutive integers, then $b^2-4 c$ equals

Solution