If $a x^2-34 x y-5 y^2+2 x+26 y-5=0$ represents a pair of straight lines, then the value of $a$ is

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Aicharya · Accepted Answer

$ a x^2-34 x y-5 y^2+2 x+26 y-5=0 $ Here, $\Delta=\left|\begin{array}{ccc}a & -17 & 1 \ -17 & -5 & 13 \ 1 & 13 & -5\end{array}ight|=0$ $ \begin{aligned} & {\left[\left|\begin{array}{lll} a & h & g \ h & b & f \ g & f & c \end{array}ight|=0ight]} \ & \Rightarrow a(-144)+17(72)-216=0 \ & \Rightarrow \quad a=7 \ & \end{aligned} $

If $a x^2-34 x y-5 y^2+2 x+26 y-5=0$ represents a pair of straight lines, then the value of $a$ is

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