If rate of reaction is given as $\frac{1}{3} \frac{\mathrm{d}[\mathrm{x}]}{\mathrm{dt}}=-\frac{1}{2}…

If rate of reaction is given as $\frac{1}{3} \frac{\mathrm{d}[\mathrm{x}]}{\mathrm{dt}}=-\frac{1}{2} \frac{\mathrm{d}[\mathrm{y}]}{\mathrm{dt}}=-\frac{\mathrm{d}[\mathrm{Z}]}{\mathrm{dt}}$, the reaction can be represented as
  1. $3 x+2 y \rightarrow Z$
  2. $2 y \rightarrow 3 x+Z$
  3. $3 x \rightarrow 2 Y+Z$
  4. $2 \mathrm{Y}+\mathrm{Z} \rightarrow 3 \mathrm{X}$

Solution

$\begin{aligned} & 2 y+z \rightarrow 3 x \\ & -\frac{1}{2} \frac{d(y)}{d t}=-\frac{d(z)}{d t}=+\frac{1}{3} \frac{d(x)}{d t}\end{aligned}$

Asked in: MHT CET 2022 (10 Aug Shift 2)

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