If radius of second stationary orbit (in Bohr's atom) is $\mathrm{R}$ then radius of third orbit will be:

If radius of second stationary orbit (in Bohr's atom) is $\mathrm{R}$ then radius of third orbit will be:
  1. $\mathrm{R} / 3$
  2. $9 \mathrm{R}$
  3. $\mathrm{R} / 9$
  4. $2.25 \mathrm{R}$

Solution

$\frac{r_{1}}{r_{2}}=\left(\frac{n_{1}}{n_{2}}ight)^{2}=\frac{4}{9}$ ,

Asked in: JEE-TOPICTESTS-CHEMISTRY

Practice more STRUCTURE OF ATOM questions on Aicharya