If $1^{\circ}=\alpha$ radians, then the approximate value of $\cos \left(60^{\circ} 1^{\prime}\right)$ is
- $\frac{1}{2}+\frac{\alpha \sqrt{3}}{120}$
- $\frac{1}{2}-\frac{\alpha}{120}$
- $\frac{1}{2}-\frac{\alpha \sqrt{3}}{120}$
- $\frac{1}{2}+\frac{\alpha}{120}$
Solution
Asked in: AP EAMCET 2011
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