If q f is the free charge on the capacitor plates and q b is the bound charge on the dielectric slab of…

If qf is the free charge on the capacitor plates and qb is the bound charge on the dielectric slab of dielectric constant k placed between the capacitor plates, then bound charge qb can be expressed as :

  1. qb=qf1-1k
  2. qb=qi1-1k
  3. qb=qf1+1k
  4. qb=qf1+1k

Solution

When a dielectric is inserted in a capacitor,

qb=qi1-1k

 

 

 

Asked in: JEE Main 2021 (25 Jul Shift 2)

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