If 'Q' is the magnitude of charge and 'r' is the distance between the centres of positive and negative…
If 'Q' is the magnitude of charge and 'r' is the distance between the centres of positive and negative charges then dipole moment $(\mu)$ is given by
$\mu=\mathrm{Q}+\mathrm{r}$
$\mu=Q \times r$
$\mu=\frac{\mathrm{Q}}{\mathrm{r}}$
$\mu=Q-r$
Solution
If ' $Q$ ' is the magnitude of charge and ' $r$ ' is the distance between the centres of positive and negative charges then dipole moment $(\mu)$ is given by $\boldsymbol{\mu}=\mathbf{Q} \times \mathbf{r}$.
Dipole moment $(\mu)$ is the product of the magnitude of the charge $(Q)$ and the distance between the centres of positive and negative charge (r).
$\therefore \mu=Q \times r$