Mathematics › Binomial Theorem › Remainder and Divisibility Problems
3200=9100
⇒(1+8)100=1+C11008+C210082+...8100⇒3200=1+8λ, where λ is some integer.⇒32008=λ+18⇒32008=18
Asked in: JEE Main 2020 (06 Sep Shift 1)
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