If optical rotation produced by the compound \((A)\) is \(+52^{\circ}\), the one produced by compound (B) is :
If optical rotation produced by the compound \((A)\) is \(+52^{\circ}\), the one produced by compound (B) is :
$-52^{\circ}$
$+52^{\circ}$
$0^{\circ}$
Unpredictable
Solution
Since (A) and (B) are enantiomers, so specific rotation of \(\mathrm{B}\) is \(-52^{\circ}\) (because enantiomers have equal and opposite specific rotation
Practice more ORGANIC CHEMISTRY – SOME BASIC PRINCIPLES AND TECHNIQUES questions on Aicharya
Practice more ORGANIC CHEMISTRY – SOME BASIC PRINCIPLES AND TECHNIQUES questions on Aicharya