If one side of an isosceles triangle is given by $y=2$ and the base is provided by the points $(2,0)$ and…
- $2 \sqrt{2}$
- $1$
- $2$
- $4$
Solution

$O A B C$ is a square. $\therefore$ Required area $=\frac{1}{2} \times$ Area of $O A B C$ $=\frac{1}{2} \times(2)^2=2$ unit $^2$
Asked in: AP EAMCET 2022 (07 Jul Shift 1)