If one root of $x^3-7 x^2+36=0$ is twice the other, then the sum of those two roots is

If one root of $x^3-7 x^2+36=0$ is twice the other, then the sum of those two roots is
  1. 6
  2. 9
  3. -9
  4. 12

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (26 Apr Shift 2)

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