If one of the lines given by $6 x^2-x y+4 c y^2=0$ is $3 x+4 y=0$, then $c$ equals

If one of the lines given by $6 x^2-x y+4 c y^2=0$ is $3 x+4 y=0$, then $c$ equals
  1. 1
  2. $-1$
  3. 3
  4. $-3$

Solution

$m_1+m_2=\frac{1}{4 c}, m_1 m_2=\frac{6}{4 c}$ and $m_1=-\frac{3}{4}$ Hence c $=-3$

Asked in: JEE Main 2004

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