If one of the lines given by $k x^2+x y-y^2=0$ bisect the angle between the co-ordinate axes, then the…
If one of the lines given by $k x^2+x y-y^2=0$ bisect the angle between the co-ordinate axes, then the values of $\mathrm{k}$ are
- 1 and 2
- 0 and 2
- 0 and -2
- -1 and 2
Solution
$\begin{aligned}
& \mathrm{kx}^2+\mathrm{xy}-\mathrm{y}^2=0 \\
& \therefore \mathrm{k}+\left(\frac{\mathrm{x}}{\mathrm{y}}\right)-\left(\frac{\mathrm{y}}{\mathrm{x}}\right)^2=0
\end{aligned}$
Slope of line is \pm 1
$\therefore \mathrm{k}+1-1=0 \text { or } \mathrm{k}-1-1=0 \Rightarrow \mathrm{k}=0,2$
Asked in: MHT CET 2021 (23 Sep Shift 1)
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