If one of the lines given by $k x^2+x y-y^2=0$ bisect the angle between the co-ordinate axes, then the…

If one of the lines given by $k x^2+x y-y^2=0$ bisect the angle between the co-ordinate axes, then the values of $\mathrm{k}$ are
  1. 1 and 2
  2. 0 and 2
  3. 0 and -2
  4. -1 and 2

Solution

$\begin{aligned} & \mathrm{kx}^2+\mathrm{xy}-\mathrm{y}^2=0 \\ & \therefore \mathrm{k}+\left(\frac{\mathrm{x}}{\mathrm{y}}\right)-\left(\frac{\mathrm{y}}{\mathrm{x}}\right)^2=0 \end{aligned}$ Slope of line is \pm 1 $\therefore \mathrm{k}+1-1=0 \text { or } \mathrm{k}-1-1=0 \Rightarrow \mathrm{k}=0,2$

Asked in: MHT CET 2021 (23 Sep Shift 1)

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