If one of the lines \(2 x^2-x y+b y^2=0\) passes through the point \((-4,-2)\), then \(b^2=\)
If one of the lines \(2 x^2-x y+b y^2=0\) passes through the point \((-4,-2)\), then \(b^2=\)
-6
36
4
16
Solution
It is given that one of the lines
\(2 x^2-x y+b y^2=0\)
passes through the point \((-4,-2)\), so
\(\begin{aligned}
& 2(-4)^2-(-4)(-2)+b(-2)^2 =0 \\
\Rightarrow & 32-8+4 b=0 \Rightarrow b =-6 \\
\therefore & b^2= 36
\end{aligned}\)
Hence, option (b) is correct.