If $65 \mathrm{~kJ}$ of work is done on the system and it releases and it releases $25 \mathrm{~kJ}$ of heat…

If $65 \mathrm{~kJ}$ of work is done on the system and it releases and it releases $25 \mathrm{~kJ}$ of heat. What is change in internal energy of the system?
  1. $16.25 \mathrm{~kJ}$
  2. $40 \mathrm{~kJ}$
  3. $90 \mathrm{~kJ}$
  4. $2.6 \mathrm{~kJ}$

Solution

$\begin{aligned} & \Delta E=\delta Q+\delta W \\ & =-25+65 \\ & =40 \mathrm{KJ}\end{aligned}$

Asked in: MHT CET 2022 (05 Aug Shift 1)

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