If $5 \mathrm{~L}$ of an ideal gas at a constant external pressure of $2 \mathrm{~atm}$ expands isothermally…

If $5 \mathrm{~L}$ of an ideal gas at a constant external pressure of $2 \mathrm{~atm}$ expands isothermally to a final volume of ' $\mathrm{X}$ ' $\mathrm{L}$, the system does a work of $-2,026.4 \mathrm{~J}$. ' $\mathrm{X}$ ' (in L) is (1 L. atm $=101.32 \mathrm{~J}$ )
  1. 25
  2. 20
  3. 15
  4. 10

Solution

$\mathrm{W}=-\mathrm{P}_{\mathrm{ext}}\left(\mathrm{V}_2-\mathrm{V}_1\right)=-2(\mathrm{x}-5)=-2026.4 \mathrm{~J}$ $\begin{aligned} & =-20 \text { L.atm } \\ & \Rightarrow-2 x+10=-20 \Rightarrow 2 x-10=20 \\ & \Rightarrow x=15 L\end{aligned}$

Asked in: AP EAMCET 2023 (17 May Shift 2)

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