If n represents the actual number of deflections in a converted galvanometer of resistance G and shunt…

If n represents the actual number of deflections in a converted galvanometer of resistance G and shunt resistance S. Then the total current I when its figure of merit is K will be
  1. KSS+G
  2. G+SnKS
  3. nKSG+S
  4. nKG+SS

Solution

Let current through galvanometer be IG and current through shunt resistance be I-IG.

Given figure of merit K=IGn

Then, total current, I=IGG+SS

I=nKG+SS

Asked in: JEE Main 2022 (25 Jun Shift 2)

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