If \(n\) is a positive integer, then \(\sum_{r=1}^n r \cdot C_r=\)
If \(n\) is a positive integer, then \(\sum_{r=1}^n r \cdot C_r=\)
- \(2^{n-1}\)
- \(n 2^{n-1}\)
- \(n 2^{n+1}\)
- \(2^{n+1}\)
Solution
\(\sum_{r=1}^n r \cdot C_r\)
\(=1 C_1+2 C_2+3 C_3+\ldots+\ldots+n C_n=n \cdot 2^{n-1}\)
Asked in: AP EAMCET 2020 (17 Sep Shift 2)
Practice more Permutation Combination questions on Aicharya