If mass of an atom is $M$ moving with speed $v$, what will be its speed after the emission of an…
- $\frac{M v}{M+2}$
- $\frac{M v}{M-4}$
- $\frac{M v}{M+4}$
- $\frac{M-4}{M N}$.
Solution
Applying the principle of momentum conservation,
$\begin{aligned}
M v & =(M-4) v^{\prime} \quad\left[\begin{array}{r}
\because \text { the speed of the } \\
\text { a-particle is zero }]
\end{array}\right. \\
\Rightarrow \quad v^{\prime} & =\frac{M v}{M-4}
\end{aligned}$Asked in: NEET 2007