If L = sin 2 π 16 - sin 2 π 8 and M = cos 2 π 16 - sin 2 π 8

1. $L=-\frac{1}{2\sqrt{2}}+\frac{1}{2}\cos \frac{\pi }{8}$
2. $L=\frac{1}{4\sqrt{2}}-\frac{1}{4}\cos \frac{\pi }{8}$
3. $M=\frac{1}{4\sqrt{2}}+\frac{1}{4}\cos \frac{\pi }{8}$
4. $M=\frac{1}{2\sqrt{2}}+\frac{1}{2}\cos \frac{\pi }{8}$

Solution

Asked in: JEE Main 2020 (05 Sep Shift 2)

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