If lines represented by equation $\mathrm{px}^2-\mathrm{qy}^2=0$ are distinct, then
If lines represented by equation $\mathrm{px}^2-\mathrm{qy}^2=0$ are distinct, then
$\mathrm{p} \mathrm{q} < 0$
$\mathrm{p}+\mathrm{q}=0$
$\mathrm{p} \mathrm{q}>0$
$\mathrm{pq}=0$
Solution
Lines represented by $\mathrm{px}^2-\mathrm{qy}^2=0$ are distinct.
Here $\mathrm{h}=0, \mathrm{a}=\mathrm{p}$ and $\mathrm{b}=-\mathrm{q}$
Now $\mathrm{h}^2-\mathrm{ab}>0 \Rightarrow 0+\mathrm{pq}>0 \Rightarrow \mathrm{pq}>0$