If $P(\theta)$ lies on the hyperbola $\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=1$ and $S$ and $S^{\prime}$…
- $a^{2} \tan ^{2} \theta-b^{2} \sec ^{2} \theta$
- $a^{2} \tan ^{2} \theta+b^{2} \sec ^{2} \theta$
- $a^{2} \sec ^{2} \theta+b^{2} \tan ^{2} \theta$
- $a^{2} \sec ^{2} \theta-b^{2} \tan ^{2} \theta$
Solution
$S P \cdot S P^{\prime}=$ By Distance formula we get;
$=a^{2} \tan ^{2} \theta+b^{2} \sec ^{2} \theta$Asked in: MHT CET 2020 (14 Oct Shift 2)