If log 10 ⁡ x 3 - y 3 x 3 + y 3 = 2 , then d y d x =

If log10x3-y3x3+y3=2 , then dydx=
  1. xy
  2. -yx
  3. -xy
  4. yx

Solution

Given, log10x3-y3x3+y3=2

x3-y3x3+y3=102=100

Applying componendo and dividendo, we get, 

x3y3=-10199xy=-1019913......(i)

Hence, y=-9910113x

Differentiating, we get,

dydx=-9910113=yx (from (i))

Asked in: MHT CET Full Test 1

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