If 8 g of a non-electrolyte solute is dissolved in 114 g of n - octane to reduce its vapour pressure to 80 % , the molar mass (in g mol - 1 ) of the solute is [Given that molar mass of n-octane is 114 g mol - 1 ]

Question

Aicharya · Accepted Answer

Assuming dilute solution, P 0 - P s P s ≈ P 0 - P s P 0 = n solute n solvent Let P 0 = 100 , V.P reduced to 80 % , ∴ P s = 80 100 - 80 100 = 8 / m 114 / 114 m = 40 g/mol.

If 8 g of a non-electrolyte solute is dissolved in 114 g of n - octane to reduce its vapour pressure to 80 %…

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