If kinetic energy of a body is increased by $300 \%$ than percentage change in momentum will be:

If kinetic energy of a body is increased by $300 \%$ than percentage change in momentum will be:
  1. $100 \%$
  2. $150 \%$
  3. $265 \%$
  4. $73.2 \%$

Solution

Here $P_1=\sqrt{2 m E_1}$ and $P_2=\sqrt{2 m E_2}$ $\begin{aligned} P^{\prime} & =\sqrt{2 m\left(E_1+\frac{300}{100} E_1\right)} \\ & =\sqrt{2 m 4 E_1} \\ & =2 P_1 \end{aligned}$

Asked in: NEET 2002

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