If K 1 and K 2 are the thermal conductivities L 1 and L 2 are the lengths and A 1 and A 2 are the cross…

If K1 and K2 are the thermal conductivities L1 and L2 are the lengths and A1 and A2 are the cross sectional areas of steel and copper rods respectively such that K2K1=9,A1A2=2,L1L2=2. Then, for the arrangement as shown in the figure. The value of temperature T of the steel - copper junction in the steady state will be

  1. 18°C
  2. 14°C
  3. 45°C
  4. 150°C

Solution

At steady state, the heat conducted by both the rods will be the same.

The rate of heat conduction is given by, dQdt=KAlT. Therefore, if the temperature of the junction is T,

K1 A1l1T1-T=K2 A2l2T-T2

450-TT-0=K2 A2l1 K1 A1l2=9×12×2

450-T=9 TT=45°C

Asked in: JEE Main 2022 (27 Jul Shift 1)

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