If $R$ is the radius of orbit of a satellite, then the kinetic energy of the satellite is
If $R$ is the radius of orbit of a satellite, then the kinetic energy of the satellite is
$\propto \frac{1}{R}$
$\propto \frac{1}{\sqrt{R}}$
$\propto R$
$\propto \frac{1}{R^{3 / 2}}$
Solution
We know that, the kinetic energy of satellite revolving around a planet of radius of orbit $R$ is
$\mathrm{KE}=\frac{G M m}{2 R}$
where, $M=$ mass of planet,
$m=$ mass of satellite
$R=$ radius of orbit
$G=$ universal gravitational constant.
$\therefore \quad \mathrm{KE} \propto \frac{1}{R}$
Hence, $\mathrm{KE}$ is inversely proportional to radius of orbit.