If $C$ is the mid point of $A B$ and $P$ is any point outside $A B$, then
- $\overrightarrow{\mathrm{PA}}+\overrightarrow{\mathrm{PB}}=2 \overrightarrow{\mathrm{PC}}$
- $\overrightarrow{\mathrm{PA}}+\overrightarrow{\mathrm{PB}}+2 \overrightarrow{\mathrm{PC}}=0$
- $\overrightarrow{\mathrm{PA}}+\overrightarrow{\mathrm{PB}}+ \overrightarrow{\mathrm{PC}}=0$
- None of these
Solution

$ \begin{aligned} & \overrightarrow{\mathrm{PA}}+\overrightarrow{\mathrm{AC}}+\overrightarrow{\mathrm{CP}}=0 \\ & \overline{\mathrm{PB}}+\overrightarrow{\mathrm{BC}}+\overrightarrow{\mathrm{CP}}=0 \end{aligned} $ Adding, we get $ \overrightarrow{\mathrm{PA}}+\overrightarrow{\mathrm{PB}}+\overrightarrow{\mathrm{AC}}+\overrightarrow{\mathrm{BC}}+2 \overrightarrow{\mathrm{CP}}=0 $ Since $\overrightarrow{A C}=-\overrightarrow{B C}$ $ \begin{aligned} & \& \overrightarrow{\mathrm{CP}}=-\overrightarrow{\mathrm{PC}} \\ & \Rightarrow \overrightarrow{\mathrm{PA}}+\overrightarrow{\mathrm{PB}}-2 \overrightarrow{\mathrm{PC}}=0 . \end{aligned} $
Asked in: JEE Main 2005