If $\mathrm{KMnO}_{4}$ is reduced by oxalic acid in an acidic medium then oxidation number of $\mathrm{Mn}$…

If $\mathrm{KMnO}_{4}$ is reduced by oxalic acid in an acidic medium then oxidation number of $\mathrm{Mn}$ changes from
  1. 4 to 2
  2. 6 to 4
  3. $+7$ to $+2$
  4. 7 to 4

Solution

In acid medium
$\mathrm{MnO}_{4}^{-}+8 \mathrm{H}^{+}+5 \mathrm{e}^{-} ightarrow \mathrm{Mn}^{2+}+4 \mathrm{H}_{2} \mathrm{O}$
(O.S. of $\mathrm{Mn}$ changes form $+7$ to $+2$ ).

Asked in: JEE-TOPICTESTS-CHEMISTRY

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