If $\mathrm{m}$ is order and $\mathrm{n}$ is degree of the differential equation $\left(\frac{d^2 y}{d x^2}\right)^5+4 \frac{\left(\frac{d^2 y}{d x^2}\right)}{\left(\frac{d^3 y}{d x^3}\right)}+\left(\frac{d^3 y}{d x^3}\right)=x^2-1$, then

Question

Aicharya · Accepted Answer

$\begin{aligned} & 	ext { We have }\left(\frac{d^2 y}{d x^2}ight)^5+\frac{4\left(\frac{d^2 y}{d x^2}ight)}{\left(\frac{d^3 y}{d x^3}ight)}+\left(\frac{d^3 y}{d x^3}ight)=x^2-1 \ & 	herefore\left(\frac{d^3 y}{d x^3}ight)\left(\frac{d^2 y}{d x^2}ight)^5+4\left(\frac{d^2 y}{d x^2}ight)\left(\frac{d^3 y}{d x^3}ight)^2=\left(x^2-1ight)\left(\frac{d^3 y}{d x^3}ight) \ & 	herefore 	ext { order }=3 	ext {, degree }=2\end{aligned}$

If $\mathrm{m}$ is order and $\mathrm{n}$ is degree of the differential equation $\left(\frac{d^2 y}{d…

Solution