If $(3,-1)$ is one end of a diameter of the circle $x^2+y^2-2 x+4 y=0$, then the equation of the tangent at…

If $(3,-1)$ is one end of a diameter of the circle $x^2+y^2-2 x+4 y=0$, then the equation of the tangent at the other end of that diameter is
  1. $2 x+y-5=0$
  2. $2 x+y+5=0$
  3. $x+2 y+5=0$
  4. $x+2 y-5=0$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (26 Apr Shift 2)

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