If $A=\left[\begin{array}{ccc}2 & 0 & -3 \\ 4 & 3 & 1 \\ -5 & 7 & 2\end{array}\right]$ is expressed as a sun…

If $A=\left[\begin{array}{ccc}2 & 0 & -3 \\ 4 & 3 & 1 \\ -5 & 7 & 2\end{array}\right]$ is expressed as a sun of a symmetric matrix $\mathrm{P}$ and skew symmetric matrix $\mathrm{Q}$, then $\mathrm{P}^{\mathrm{T}}-\mathrm{Q}^{\mathrm{T}}=$
  1. $\left[\begin{array}{ccc}8 & -16 & -4 \\ 2 & 8 & 7 \\ 6 & 14 & -16\end{array}\right]$
  2. $\left[\begin{array}{ccc}2 & 0 & -3 \\ 4 & 3 & 1 \\ -5 & 7 & 2\end{array}\right]$
  3. $\left[\begin{array}{ccc}2 & 4 & -5 \\ 0 & 3 & 7 \\ -3 & 1 & 2\end{array}\right]$
  4. $\left[\begin{array}{ccc}1 & 0 & -3 / 2 \\ 2 & 3 / 2 & 1 / 2 \\ -5 / 2 & 7 / 2 & 1\end{array}\right]$

Solution

Given : $A=\left[\begin{array}{ccc}2 & 0 & -3 \\ 4 & 3 & 1 \\ -5 & 7 & 2\end{array}\right]$ Since, each and every matrix can be written as sum of symmetric \& skew symmetric matrix. $\therefore$ A can be written as sum symmetric matrix $P$ and skew symmetric matrix Q. where $\mathrm{P}=\frac{1}{2}\left[\mathrm{~A}+\mathrm{A}^{\mathrm{T}}\right]$ $ \mathrm{Q}=\frac{1}{2}\left[\mathrm{~A}-\mathrm{A}^{\mathrm{T}}\right] $ $ \begin{aligned} & \text { Now, } A^T=\left[\begin{array}{ccc} 2 & 4 & -5 \\ 0 & 3 & 7 \\ -3 & 1 & 2 \end{array}\right] \\ & \therefore P=\frac{1}{2}\left[\begin{array}{ccc} 4 & 4 & -8 \\ 4 & 6 & 8 \\ -8 & 8 & 4 \end{array}\right]=\left[\begin{array}{ccc} 2 & 2 & -4 \\ 2 & 3 & 4 \\ -4 & 4 & 2 \end{array}\right] \\ & Q=\frac{1}{2}\left[\begin{array}{ccc} 0 & -4 & 2 \\ 4 & 0 & -6 \\ -2 & 6 & 0 \end{array}\right]=\left[\begin{array}{ccc} 0 & -2 & 1 \\ 2 & 0 & -3 \\ -1 & 3 & 0 \end{array}\right] \\ & \mathrm{P}^T=\left[\begin{array}{ccc} 2 & 2 & -4 \\ 2 & 3 & 4 \\ -4 & 4 & 2 \end{array}\right] Q^T=\left[\begin{array}{ccc} 0 & 2 & -1 \\ -2 & 0 & +3 \\ 1 & -3 & 0 \end{array}\right] \end{aligned} $ $\mathrm{P}^{\mathrm{T}}-\mathrm{Q}^{\mathrm{T}}=\left[\begin{array}{ccc}2-0 & 2-2 & -4+1 \\ 2+2 & 3-0 & 4-3 \\ -4-1 & 4+3 & 2-0\end{array}\right]=\left[\begin{array}{ccc}2 & 0 & -3 \\ 4 & 3 & 1 \\ -5 & 7 & 2\end{array}\right]$

Asked in: AP EAMCET 2023 (18 May Shift 2)

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